18x^2-(9x+2)*(2x-1)=1

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Solution for 18x^2-(9x+2)*(2x-1)=1 equation: 



18x^2-(9x+2)(2x-1)=1

We move all terms to the left:

18x^2-(9x+2)(2x-1)-(1)=0

We multiply parentheses ..

18x^2-(+18x^2-9x+4x-2)-1=0

We get rid of parentheses

18x^2-18x^2+9x-4x+2-1=0

We add all the numbers together, and all the variables

5x+1=0

We move all terms containing x to the left, all other terms to the right

5x=-1

x=-1/5

x=-1/5

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